Hello, On 03.12.2009, at 13:08, Jim Reid wrote:
On 3 Dec 2009, at 10:00, <michael.dillon@bt.com> wrote:
an IPv6 /24 and an IPv4 /24 use up the same percentage of the total address space.
How do you work that out? Please enlighten me. 2^24/2^128 x 100 is many orders of magnitude smaller than 2^24/2^32 x 100: gromit% bc scale=50 2^24/2^128*100 .00000000000000000000000000000493038065763132378300 2^24/2^32*100 .39062500000000000000000000000000000000000000000000
Actually the size of a /24 is 2^(128-24) or 2^(32-24), sooo: 2^(32-24) / 2^32 * 100 = 1/2^24 * 100 and 2^(128-24) / 2^128 * 100 = 1/2^24 * 100 Or am I missing something here:
There are of course the same number of IPv4 and IPv6 /24s.
If the Number of /24s is the same every one of them uses the same percentage of the Address-Space: 100 / (# of /24s) lGuk -- Ulrich Kiermayr jabber xmpp:uk@jabber.univie.ac.at Leiter der Abteilung Datennetz und Telefonie skype:kiermayr Vienna University Computer Center phone +43 1 4277 14020 Universitaetsstrasse 7, 1010 Wien, AT fax +43 1 4277 9140